The TI89 and MultiVariable Limits (also MultiVariable Limits in General):
I wrote this in response to a question that I saw was answered incorrectly in a forum:
lim(f(x,y)) as (x,y) > (0,0) does not always exist just because lim(f(x,0)) as (x,0) > (0,0) = 0 and lim(f(0,y)) as (0,y) > (0,0) = 0
You need to check cases OTHER than just going along the xaxis (when y = 0) and the yaxis (when x =0)
If you have James Stuart's Multivariable Calculus (either the third and fourth editions) look at Chapter 11  section 2, example 2.
f(x,y) = (x*y)/(x^2+y^2)
lim(f(x,0)) as (x,0) > (0,0) = 0 and lim(f(0,y)) as (0,y) > (0,0) = 0, but...
... What if we take the limit by going along the line y=x?
so, f(x,x) = (x*x)/(x^2+x^2) = (x^2)/(x^2+x^2)
lim(f(x,x)) as (x,y) > (0,0) = 1/2
Therefore, since different limits are obtained at the same point, the given limit of f(x,y) > (0,0) does NOT exist.
In actuality, the are an infinite number of paths one could check and if just ONE of them does not equal the others then the limit does not exist.
So, you could say let y = m*x (this would cover all lines) on the xyplane (x or y not equal to zero)
So then f(x,y) = f(x,m*x)
Let, f(x,x*m) = (x*(x*m))/(x^2+(x*m)^2) = (x^2)/(x^2+(x*m)^2)
And, lim((x*m*x)/(x^2+(x*m)^2) as (x,x*m) > (0,0) = (m/(m^2 + 1))
If the 'm' (slope) of the line is any number not equal to zero then there will be a infinite amount of results that are defined.
So, the point is just because lim(f(x,0)) as (x,0) > (0,0) = 0 and lim(f(0,y)) as (0,y) > (0,0) = 0
Does not ALWAYS mean the limit of the function exists or is zero.
So, if you enter lim(lim((x*y)/(x^2+y^2),x,0),y,0) in your TI89 it outputs 0.
But, that answer is NOT correct. In fact, the limit DOES NOT exist.
In conclusion, do NOT trust your calculator by ONLY checking the limit along x=0 and y = 0 such as what this command "lim(lim((x*y)/(x^2+y^2),x,0),y,0)" does, you rather need to check other paths and make sure they also give zero.
Also, all one needs to find is ONE counterexample to show or prove that something is false in mathematics.
